∴ Centre Of Circle (− A, − A) [∵ The Circle Touches Both The Axes And Lies In The Third Quadrant] Given That The Line 3 X − 4 Y + 8 = 0 Touches The Circle.
Answer by josgarithmetic (37728) ( show. The equation to a circle is. ★★ tamang sagot sa tanong:
This Problem Has Been Solved!
We also know the derivative of the circle equation (with respect to x ): ∴ 3 x − 4 y + 8 = 0 is tangent to the circle. Tangent to both axes, center in the second quadrant, radius 4.
( X − X C) 2 + ( Y − Y C) 2 = R 2.
\(c\) is the center of the ellipse. The standard equation for a circle is. If a point p on the axis of the parabola y 2 = 4 x is taken such that the point is at shortest distance from the circle x 2 + y 2 + 2 x − 2 √ 2 y + 2 = 0.common tangents are drawn to the circle and.
In Third Quadrant, Both X And Y Are Negative, Therefore.
So in question, it is given that the circle lies in the second quarter and the x x and y axes both are tangent to the circle. 2 x + 2 ( y − y c) y ′. The equation to a circle is.
One Way I Thought Of Doing It Was Letting The Center Point Of The Circle Be The.
The center can be translated by subtracting from the x. So the blue uh blue one is a circle which is lying in the second. Find an equation of the circle that satisfies the stated conditions.