As O C = A C.
Diagram shows a circle, centre o and radius 8 cm inscribed in a sector spt of a circle at centre p. In the following figure, o is the centre of the circle, ∠aob = 60° and ∠bdc = 100° find ∠obc. Oabc is a parallelogram so ab = oc and oa = bc triangles aob and boc are equilateral.
Solution Verified By Toppr In Given Figure ,O Is The Center Of Circle.
Given o is the centre of the circle and ∠aob = 70°. Draw a circle with centre. If the radius of the circle is 3 cm and oc is the perpendicular drawn on ab from centre.
However, If A Triangle Has One 60 Degree Angle, And The Two Sides Of.
The tangents to the circle at a and b meet at a point p. We have a circle with centre o and two radii oa and ob. Ab is a chord in the minor segment of a circle with centre o.
∴ ∠Oab Is An Equilateral Triangle So Perimeter = 3 + 3 + 3 = 9 Cm.
Mathematically, we have the area of the sector as; Pram6jj pram6jj 20.03.2018 math secondary school answered o is the. Here, ∠aob= 2∠acb (angle at the.
O Is The Centre Of The Circle.
(1) second, given that perimeter of triangle aob is equal to. In the figure above, point o is the center of the circle and oc = ac = [ #permalink ] updated on: Oa = ob = r hence triangle oab is iscocele triangle.